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ABC is an isosceles triangle with AB=AC and ∠BAC=40∘\angle BAC=40^{\circ}∠BAC=40∘. P is a point inside the triangle such that ∠PBC=30∘\angle PBC=30^{\circ}∠PBC=30∘ and ∠PCB=50∘\angle PCB=50^{\circ}∠PCB=50∘. Find ∠APB\angle APB∠APB.
Note: Use only geometry to solve the problem.
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