Forgot password? New user? Sign up
Existing user? Log in
∑k=1∞∑n=0∞(−1)k−1k(1+2nk)\large \sum_{k = 1}^{\infty} \sum_{n = 0}^{\infty} \frac{(-1)^{k - 1}}{k(1 + 2^nk)} k=1∑∞n=0∑∞k(1+2nk)(−1)k−1
Find the value (to 2 decimal places) of the closed form of the expression above.
Problem Loading...
Note Loading...
Set Loading...