A Series of Logarithms

Algebra Level 1

If x=2015! x = 2015! then evaluate

1log2x+1log3x+1log4x++1log2015x. \frac { 1 }{ \log _{ 2 }{ x } } +\frac { 1 }{ \log _{ 3 }{ x } } +\frac { 1 }{ \log _{ 4 }{ x } } + \ldots + \frac { 1 }{ \log _{ 2015 }{ x } }.

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