A simple recursion for 2016 and 2018!

Algebra Level 4

xn+1=1+xn1xn\large x_{n+1} = \dfrac{1+x_n}{1-x_n} Consider the recurrence relation above with x0=2016x_0 = 2016 . Compute 10000x2018 \lfloor 10000 | x_{2018} | \rfloor .

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