A simplified version of simple question

Geometry Level 2

(tanθ+secθ)(tanα+secα)=1\large (\tan \theta + \sec \theta)(\tan \alpha + \sec \alpha) = 1

Given the above, find tan2θsec2α\tan^2 \theta - \sec^2 \alpha for θ[π2,π2]\theta \in \left[-\frac \pi 2, \frac \pi 2 \right]

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