# A Thoughtful Journey

A train is moving along a straight line with a constant acceleration $$'a’$$. A boy standing in the train throws a ball forward with a speed of $$10 m/s$$, at an angle of $$60$$ to the horizontal. The boy has to move forward by $$1.15 m$$ inside the train to catch the ball back at the initial height. The acceleration of the train, in $$m/s^{2}$$ , is

Note: Angle is in Degree Measure , g = $$10 m/s^{2}$$ and take $$\sqrt{3} = 1.73$$

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