A train is moving along a straight line with a constant acceleration *\('a’\)*. A boy standing in
the train throws a ball forward with a speed of **\(10 m/s\)**, at an angle of **\(60\)**
to the horizontal.
The boy has to move forward by **\(1.15 m\)** inside the train to catch the ball back at the initial
height. The acceleration of the train, in \(m/s^{2}\)
, is

*Note*: **Angle is in Degree Measure** , **g = \(10 m/s^{2}\)** and take **\(\sqrt{3} = 1.73\)**

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