A Thoughtful Journey

A train is moving along a straight line with a constant acceleration \('a’\). A boy standing in the train throws a ball forward with a speed of \(10 m/s\), at an angle of \(60\) to the horizontal. The boy has to move forward by \(1.15 m\) inside the train to catch the ball back at the initial height. The acceleration of the train, in \(m/s^{2}\) , is

Note: Angle is in Degree Measure , g = \(10 m/s^{2}\) and take \(\sqrt{3} = 1.73\)

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