A ball is projected with a speed of \(20 \text{ m/s}\) at an angle of \(30^\circ\) from a point on the top of a very high tower. The time after which its velocity becomes perpendicular to the velocity of projection (take g = 10 \(m/s^2\)) is

If you have the solution then please post it with an explanation.

×

Problem Loading...

Note Loading...

Set Loading...