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∫0π/2cotxcotx+tanx dx= ?\int _{ 0 }^{ { \pi } / { 2 } }{ \dfrac { \sqrt { \cot{x} } }{ \sqrt{\cot{x}}+ \sqrt{\tan{x}}}} \, dx = \, ? ∫0π/2cotx+tanxcotxdx=?
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