An AC circuit is given below:

The source voltage is given by \(V=V_o sin (\omega t)\) where \(\omega\) is the angular frequency, \(t\) is time and \(V_o\) is the peak voltage. At \(t=0\) current drawn from the source is \(0 A\) and it begins to flow in the direction as shown. Assume that the diodes do not allow any current to flow through them in the reverse biased condition. At \(t= \frac{7\pi}{6\omega}\), current flows through:

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