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Find the smallest positive real xxx such that ⌊x2⌋−x⌊x⌋=6.\big\lfloor x^2 \big\rfloor-x\lfloor x \rfloor=6.⌊x2⌋−x⌊x⌋=6. If your answer is in the form ab\frac{a}{b}ba, where aaa and bbb are coprime positive integers, submit your answer as a+b.a+b.a+b.
Notation: ⌊⋅⌋ \lfloor \cdot \rfloor ⌊⋅⌋ denotes the floor function.
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