Forgot password? New user? Sign up
Existing user? Log in
1212+(1+2)222+⋯+(1+2+3+⋯+16)2162= ? \dfrac{1^2}{1^2} + \dfrac{(1+2)^2}{2^2} + \cdots + \dfrac{(1+2+3+\cdots+16)^2}{16^2} = \, ? 1212+22(1+2)2+⋯+162(1+2+3+⋯+16)2=?
Problem Loading...
Note Loading...
Set Loading...