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x+y=(xy+yx)2\displaystyle{{ x }+{ y }={ \left( \cfrac { \sqrt { x } }{ \sqrt { y } } +\cfrac { \sqrt { y } }{ \sqrt { x } } \right) }^{ 2 }}x+y=(yx+xy)2
xxx and yyy are positive real numbers satisfying the above equation.
Find Maximum value of 24x+7y+31xyxy\displaystyle{\cfrac { 24\sqrt { x } +7\sqrt { y } +31\sqrt { xy } }{ \sqrt { xy } } }xy24x+7y+31xy
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