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P(x)=x6+(x−r)6+(x−2r)6−3r\large P(x)=x^6+(x-r)^6+(x-2r)^6-3rP(x)=x6+(x−r)6+(x−2r)6−3r The polynomial above has exactly two real zeros. Find the value of rrr such that the sum of the real zeros is 111.
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