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Let s=∑n=0∞(−1)n(n+1)(n+2).\large s=\sum_{n=0}^\infty \frac{(-1)^n}{(n+1)(n+2)}.s=n=0∑∞(n+1)(n+2)(−1)n. Find es+1e^{s+1}es+1.
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