2016 AMC 12B Problem 22

For a certain positive integer \(n\) less than 1000, the decimal equivalent of \(\dfrac{1}{n}\) is \(0.\overline{abcdef}\), a repeating decimal of period 6, and the decimal equivalent of \(\dfrac{1}{n+6}\) is \(0.\overline{wxyz}\) a repeating decimal of period 4. In which interval does \(n\) lie?


Check out the whole set: 2016 AMC 12B Problems.
×

Problem Loading...

Note Loading...

Set Loading...