Forgot password? New user? Sign up
Existing user? Log in
If a2−1b2b2−1a2=9\dfrac { { a }^{ 2 }-\dfrac { 1 }{ { b }^{ 2 } } }{ { b }^{ 2 }-\dfrac { 1 }{ { a }^{ 2 } } } =9 b2−a21a2−b21=9, then what is the value of ∣ab∣ \left| \dfrac { a }{ b } \right| ∣∣∣ba∣∣∣?
and ∣ab∣≠1 \left| ab \right| \neq 1 ∣ab∣=1
Problem Loading...
Note Loading...
Set Loading...
