# An algebra problem by Ahmed Abdelbasit

**Algebra**Level 2

the price of the \(1^{st}\) type is (5.00) $

the price of the \(2^{nd}\) type is (1.00) $

the price of the \(3^{rd}\) type is (0.05) $

if we consider that :

the number of the \(1^{st}\) type is A

the number of the \(2^{nd}\) type is B

the number of the \(3^{rd}\) type is C

so that A+B+C = 100

what is the value of \(\frac{C+10}{A-10B}\)