An algebra problem by Ahmed Abdelbasit

Algebra Level 2

you have (100$) and wanna buy 100 pen .. but you found out that there are three types of pens .. and you wanna buy 100 pen containing all three types and also spend the all 100 dollars ..

the price of the \(1^{st}\) type is (5.00) $

the price of the \(2^{nd}\) type is (1.00) $

the price of the \(3^{rd}\) type is (0.05) $

if we consider that :

the number of the \(1^{st}\) type is A

the number of the \(2^{nd}\) type is B

the number of the \(3^{rd}\) type is C

so that A+B+C = 100

what is the value of \(\frac{C+10}{A-10B}\)

×

Problem Loading...

Note Loading...

Set Loading...