its easy!

Algebra Level 3

1x+1+2y+2+2006z+2006=1findx2x2+x+y2y2+2y+z2z2+2006z\frac { 1 }{ x+1 } +\frac { 2 }{ y+2 } +\frac { 2006 }{ z+2006 } =1\\ find\\ \frac { { x }^{ 2 } }{ { x }^{ 2 }+x } +\frac { { y }^{ 2 } }{ { y }^{ 2 }+2y } +\frac { { z }^{ 2 } }{ { z }^{ 2 }+2006z }

Assume that (x2+x)(y2+2y)(z2+2006z)0 (x^2+x)(y^2+2y)(z^2+2006z) \neq 0 .

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