Premature Termination

Let there be a sequence \( a_1, a_2, a_3 \dots \dots a_{2014} \). Let \( a_1 \) be \( 2014 \). If the next number in the series is the sum of the cubes of the digits of the previous number, what is the \( 2014^{\text{th}} \) number in the sequence?

×

Problem Loading...

Note Loading...

Set Loading...