Premature Termination

Let there be a sequence a1,a2,a3a2014 a_1, a_2, a_3 \dots \dots a_{2014} . Let a1 a_1 be 2014 2014 . If the next number in the series is the sum of the cubes of the digits of the previous number, what is the 2014th 2014^{\text{th}} number in the sequence?

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