An algebra problem by K. J. W.

Algebra Level 4

Let X=\({ \left( -1+\frac { 2 }{ -2+\frac { 2 }{ -2+\frac { 2 }{ -2+\frac { 2 }{ -2+... } } } } \right) }^{ 1000 }\) Reverse the last two integral digits of X to form a two-digit number Y.

Find the value of \(\left\lfloor \frac { Y }{ 3 } \right\rfloor\).

P.S. -1 is not an error

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