# Just H and S

Calculus Level 3

If $H = \displaystyle \sum_{n=1}^{\infty} \frac{n^{3}}{(n - 1)!}$ and $S = \displaystyle \sum_{n=1}^{8} \frac{n}{1+n^{2}+n^{4}}$

The value of $$H = A\cdot e$$ and value of $$S = \frac{B}{C}$$.Then find $$A+B+C$$ .

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