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a100−b100a98(a+1)−b98(b+1)\sqrt{\frac{a^{100} - b^{100}}{a^{98}(a+1) - b^{98}(b+1)}} a98(a+1)−b98(b+1)a100−b100 Let a,ba,ba,b be the roots of x2−x−1=0x^2 - x -1 = 0x2−x−1=0, then find the value of the above expression.
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