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x2−1x+1+(x+1)2−1x+2+(x+2)2−1x+3 \dfrac{x^2-1}{x+1} + \dfrac{(x+1)^2-1}{x+2} + \dfrac{(x+2)^2-1}{x+3} x+1x2−1+x+2(x+1)2−1+x+3(x+2)2−1
Given that x>0x>0x>0, the expression above simplifies to:
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