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Algebra Level 1

Find the value of:

$x\quad =\quad \frac { \frac { \sqrt [ 3 ]{ a } }{ { a }^{ 2 } } }{ \frac { 1 }{ 4a } } \quad -\quad 1\\ \\ \\ \\ y\quad =\quad \frac { \frac { \sqrt [ 3 ]{ x } \quad +\quad 1 }{ { x }\quad +\quad 1 } }{ \frac { x }{ 1 } \quad +\quad 1 } \quad +\quad 1$

If a = 8.

Then what is ${ |-x-y| }^{ 0 }$