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Find the value of:
x=a3a214a−1y=x3+1x+1x1+1+1x\quad =\quad \frac { \frac { \sqrt [ 3 ]{ a } }{ { a }^{ 2 } } }{ \frac { 1 }{ 4a } } \quad -\quad 1\\ \\ \\ \\ y\quad =\quad \frac { \frac { \sqrt [ 3 ]{ x } \quad +\quad 1 }{ { x }\quad +\quad 1 } }{ \frac { x }{ 1 } \quad +\quad 1 } \quad +\quad 1x=4a1a23a−1y=1x+1x+13x+1+1
If a = 8.
Then what is ∣−x−y∣0{ |-x-y| }^{ 0 }∣−x−y∣0
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