# An algebra puzzle

Algebra Level 3

We know that

$$(1-\frac{1}{2^2})*(1-\frac{1}{3^2})*(1-\frac{1}{4^2})*\dots*(1-\frac{1}{n^2})=k$$

where $$n$$ is a positive integer.

If $$k$$ can't be $$\frac{1}{2}$$ and can't be $$\frac{1008}{2017}$$, then choose 0.

If $$k$$ can't be $$\frac{1}{2}$$, but it can be $$\frac{1008}{2017}$$, then choose 1.

If $$k$$ can't be $$\frac{1008}{2017}$$, but it can be $$\frac{1}{2}$$, then choose 2.

If $$k$$ can be $$\frac{1}{2}$$ and $$\frac{1008}{2017}$$ too, then choose 3.

×

Problem Loading...

Note Loading...

Set Loading...