# A Question

Algebra Level 4

Let $$x$$ be a positive number such that $$\left\lfloor { x }^{ 2 } \right\rfloor +\left\lfloor x \right\rfloor =15$$. If the restriction of $$x$$ is $$a\le x<b$$ , what is $$(a+b)$$?

Round your answer to 2 decimal places.

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