Electrons are ejected from the electron gun with negligible velocity. These emitted electrons are then accelerated across a potential difference \(V\) along the \(x\)-axis. These electrons emerge from a narrow hole into a region of uniform magnetic field \(B\). However, some of the electrons emerging from the hole make **slightly** divergent angles as shown in the figure above. If the **paraxial** electrons are refocused on the \(x\)-axis. at a distance \(\sqrt{\dfrac{A \pi^2 mV}{eB^2}}\) from the hole, then find the value of \(A\).

**Notations**:

\(m\) deontes the mass of electron.

\(e\) denotes the magnitude of charge on an electron.

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