# Charged Pendulum!

A charged particle having its charge to mass ratio as $$\beta$$ goes in a conical pendulum of length $$L$$ making an angle $$\theta$$ with vertical and angular velocity $$\omega$$. If a magnetic field $$B$$ is directed vertically downwards (see figure), then:

$$(A) B = \frac{1}{\beta}[\omega - \frac{g}{\omega L \cos \theta}]$$

$$(B)$$ Angular momentum of the particle about the point of suspension remains constant .

$$(C)$$ If the direction of $$B$$ were reversed maintaining same $$\omega$$ and $$L$$, then $$\theta$$ will remain unchanged.

$$(D)$$ Rate of change of angular momentum of the particle about the point of suspension is not a constant vector.

×