A problem from my book-10!
An Ammeter and a voltmeter is shown in figure-1 . A naughty boy came and interchange the markings of ammeter and voltmeter together as shown in figure-2
(now if the actual potential drop across voltmeter is 6 V it will show 4V)
. Now the changed ammeter and voltmeter is connected in a R-C circuit as shown in figure-3 .
The resistance is of 0.25 ohm and capacitor is of 4 micro farad.. Find the time in which both the ammeter and voltmeter show same readings.( E<1V)
The answer is of form t= (10^a ) ln(b) s. Find a x b.
ammeter and voltmeter are not interchanged only there markings are interchanged.
it is obvious that if we are using voltmeter readings is in volts and if we are using ammeter reading is in amperes
Assume voltmeter ,ammeter and battery ideal