How many times is the electrostatic force of attraction, between two electrons separated by a distance of 'r' meters, greater than the gravitational force of attraction?

The answer is in the form \(a\times10^b\)(in standard form), provide the answer as \(\lfloor a+b\rfloor\).

**Details and Assumptions:**

Charge on an electron \(=1.6\times 10^{-19}\text{C}\),

Mass of electron \(= 9\times 10^{-31}\text{Kg}\)

Gravitational Constant \(=6\times 10^{-11}\text{Nm}^2\text{/kg}^2\) and

\(\dfrac 1{4\pi\epsilon_0}=9\times 10^9\text{Nm}^2\text{/C}^2\).

\(\lfloor.\rfloor\) is the Floor function

**Note:** The values given above are approximations, do not use them as specific values.

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