# Electrostatics vs Gravitation!

How many times is the electrostatic force of attraction, between two electrons separated by a distance of 'r' meters, greater than the gravitational force of attraction?

The answer is in the form $a\times10^b$(in standard form), provide the answer as $\lfloor a+b\rfloor$.

Details and Assumptions:

• Charge on an electron $=1.6\times 10^{-19}\text{C}$,

• Mass of electron $= 9\times 10^{-31}\text{Kg}$

• Gravitational Constant $=6\times 10^{-11}\text{Nm}^2\text{/kg}^2$ and

• $\dfrac 1{4\pi\epsilon_0}=9\times 10^9\text{Nm}^2\text{/C}^2$.

• $\lfloor.\rfloor$ is the Floor function

Note: The values given above are approximations, do not use them as specific values.

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