The following is my attempt at proving that $1 < -1$. In which of these steps did I first make a mistake by using flawed logic?

**Step 1:** Let $i = \sqrt{-1}$, then $i^2 = -1$ and $i^4 = \big(i^2\big)^2 = (-1)^2 = 1$.

**Step 2:** Hence, we have $i^2 < i^4$.

**Step 3:** We divide both sides by $i$ to get $i < i^3$.

**Step 4:** We divide both sides by $i$ again to get $1 < i^2$ or, equivalently, $1 < -1$.

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