# An interesting equation

Algebra Level 4

The equation $$x^3+12x^2-x-7=0$$ has three real roots. Now, the equation $$ay^3+by^2-cy+d=0$$ has the roots of the previous equation increased by $$4$$, where $$\text{gcd}(a,b,c,d)=1$$. Find $$a+b+c+d$$

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