We have 2 litre \(\ce{NaOH}\) 1.5N we need to raise the concentration to become 3.6N by adding a known volume from stock solution whose concentration is 5.2N

Then we need to convert all \(\ce{NaOH}\) in the resulting solution (whose concentration is 3.6 and it's volume is unknown) into \(\ce{NaCl}\) by adding \(\ce{HCl}\) 37% w/w and it's specific gravity is 1.19 gm/ml and it's molecular weight is 36.46 so calculate the exact volume of \(\ce{HCl}\) needed without any excess.

Write the volume in litres to the nearest one decimal.

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