And this was after a few.

Level pending

Two aged Number theory specialists sit at a bar.

Anthony said, "It just occurred to me that when we first met, the square of your age contained the same three digits as the square of my age, just in a different order."

Bradley said, "If you take the square of the sum of our ages when we met and split it into two 2-digit numbers, you'd have my age then and your age now"

1234 split into two 2 digit numbers results in 12 and 34.

let B = Bradley's age now and A = Anthony's age now, B/A = x/y where x and y are positive co prime integers.

c^2 = xy+y

If, on the day he met Bradley, Anthony added c to his age, 2c being smaller than Bradley's age (then). what answer would he arrive at?


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