# Angular Mechanics + Kinematics

Classical Mechanics Level pending

A particle is projected at $$t$$$$=$$$$0$$ from a point $$P$$ on the ground with a speed $$v_\circ$$ at an angle of $$45^\circ$$ to the horizontal. The magnitude of the angular momentum of the particle about $$P$$ at time $$t$$$$=$$$$(\frac{v_\circ}{g}$$) can be expressed as $$4$$$$\times$$$$10^\tau$$$$.$$ Find $$\tau$$.

Note: Take $$v_\circ$$ to be $$1$$$$\frac{m}{s}$$, mass of particle to be $$1 \text{ kg}$$, $$\sqrt{2}$$$$=$$$$1.4$$ and $$g$$$$=$$$$10(\frac{m}{s^2}$$)$$.$$

Also make approximations where necessary.

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