Another 0=1 Proof

Here's my proof that $0=1$.
In which of these steps did I first make a flaw in my logic?

Step 1: Let's establish the following equations first, $\begin{aligned} 0 \times 0 \times 0 \times 0 &=& 0 \\ 0\times 0 \times 0 &=& 0 \end{aligned}$

Step 2: Since both these numbers are equal in value, then their ratio is equal to 1.

$\dfrac{ 0 \times 0 \times 0 \times 0}{ 0\times 0 \times 0 } = 1$

Step 3: Cancel out common factors:

$\begin{aligned} \dfrac{ 0 \times \xcancel0 \times \xcancel0 \times \xcancel0}{ \xcancel0\times \xcancel0 \times \xcancel0 } &=& 1 \\ 0 &=& 1 \end{aligned}$