# Another 0=1 Proof

**Algebra**Level 1

Here's my proof that \(0=1\).

In which of these steps did I **first** make a flaw in my logic?

**Step 1**: Let's establish the following equations first,
\[ \begin{eqnarray} 0 \times 0 \times 0 \times 0 &=& 0 \\ 0\times 0 \times 0 &=& 0 \end{eqnarray} \]

**Step 2**: Since both these numbers are equal in value, then their ratio is equal to 1.

\[ \dfrac{ 0 \times 0 \times 0 \times 0}{ 0\times 0 \times 0 } = 1 \]

**Step 3**: Cancel out common factors:

\[\begin{eqnarray} \require{cancel} \dfrac{ 0 \times \xcancel0 \times \xcancel0 \times \xcancel0}{ \xcancel0\times \xcancel0 \times \xcancel0 } &=& 1 \\ 0 &=& 1 \end{eqnarray} \]

**Your answer seems reasonable.**Find out if you're right!

**That seems reasonable.**Find out if you're right!

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