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11×2×3+12×3×4+13×4×5+...+198×99×100\frac{1}{1 \times 2 \times 3} + \frac{1}{2 \times 3 \times 4} + \frac{1}{3 \times 4 \times 5} + ... +\frac{1}{98 \times 99 \times 100} 1×2×31+2×3×41+3×4×51+...+98×99×1001.
The expression above can be expressed in a form of 1p−1q \dfrac{1}{p} - \dfrac{1}{q}p1−q1, where pp p and qqq are positive integers. Find the value of p+qp+qp+q.
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