Another Summation

Algebra Level 5

\[ \large\displaystyle\sum_{n=8}^{ \infty}\dfrac{1}{(n-4)(n-2)n(n+2)(n+4)} \]

The summation above is equal to \(\dfrac{a}{b} \), where \(\text{gcd}(a,b) = 1\). Find \( a+b\).


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