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{a4+(ab)2+b4=900a2+ab+b2=45\large{\\ \\ \begin{cases} { a }^{ 4 }+{ ( ab ) }^{ 2 }+{ b }^{ 4 }=900 \\ { a }^{ 2 }+ab+{ b }^{ 2 }=45 \end{cases}}⎩⎨⎧a4+(ab)2+b4=900a2+ab+b2=45
Let aaa and bbb be real numbers that satisfy the equation above. Find the value of 2ab2ab2ab.
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