Another unusual cryptogram

Logic Level 5

×=\huge{\Box \times \Box \Box = \Box \Box \Box}

Fill the boxes above with the digits 2,3,4,5,6,72,3,4,5,6,7, with no digit repeated, such that the equation is true.

There are two solutions to the above puzzle. Enter your answer as the sum of the two possible three-digit integers. For example, if the solutions are 2×34=5672 \times 34 = 567 and 7×65=4327 \times 65 = 432, enter 567+432=999567 + 432 = 999.

Also try its sister problem.


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