In the Fig , block 2 of mass \(2.0\) kg oscillates on the end of a spring in SHM with a period of \(20\) ms. The position of the block is given by \(x (t )= (1.0 cm)\ cos (\omega t + \pi/2)\) . Block \(1\) of mass\( 4.0 \)kg slides toward block \(2\) with a velocity of magnitude \(6.0 \)m/s, directed along the springâ€™s length.The two blocks undergo a completely inelastic collision at time \(t = 5.0\)ms. (the duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision?

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