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In the Fig , block 2 of mass 2.02.0 kg oscillates on the end of a spring in SHM with a period of 2020 ms. The position of the block is given by x(t)=(1.0cm) cos(ωt+π/2)x (t )= (1.0 cm)\ cos (\omega t + \pi/2) . Block 11 of mass4.0 4.0 kg slides toward block 22 with a velocity of magnitude 6.06.0 m/s, directed along the spring’s length.The two blocks undergo a completely inelastic collision at time t=5.0t = 5.0ms. (the duration of the collision is much less than the period of motion.) What is the amplitude of the SHM after the collision?

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