Anti-Gravity in projectiles

In the vertical xy plane a particle is projected with a velocity 10m/s 10 m/s making an angle 450 { 45 }^{ 0 } with the +ve +ve x-axis. Acceleration due to gravity is 10jm/s2 -10j m/{ s }^{ 2 } .

At time t=α t=\alpha sec the anti-gravity switch is turned on. Now the acceleration is 10jm/s2 10j m/{ s }^{ 2 } . If the particle passes through the point (30,20) (30, 20) during it's motion then: Find α \alpha .

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