# Anyhow bringing 11 in a problem ?

Given a recurrence relation $a_0=0$, $a_1=1$ and for $n\geq 2$ , $a_n=6a_{n-1} -9a_{n-2}$ find the remainder when $a_{20}$ is divided by $11$ ?

This is a part of the set 11≡ awesome (mod remainders)

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