Above shows a square \(ABCD\) with side length \(a=10\). There is a point \(E\) inside that square, that forms four triangles \(F\),\(G\),\(H\) and \(I\) with the corners of the square \(A\),\(B\),\(C\) and \(D\), respectively as shown in the picture above.

Find the sum of areas, \(F+H\).

If you think there are not enough information to solve, type 3141 as your answer.

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