# Ball Packing Wars

**Geometry**Level 5

Neither is using the simple cubic packing, because they both know that it's an inefficient way to pack balls in boxes. Both are close-packing the balls, meaning that the balls are tightly packed, and any gaps between the stack of balls and the inside walls of the cube boxes are filled with packing material. They get into an argument about who's packing more efficiently.

Alex says, "We know that both methods will ultimately have the exact same packing density, which is \(\dfrac { \pi }{ 3\sqrt { 2 } } \) or about \(74\)%, but that's true only as a limit. Because this box has right angles, it's better that I start with balls packed in a square array at the bottom, and work my way up. It is so obvious."

Bill says, "Maybe obvious to you, but I find that by using the hexagonal array, I have more opportunities to pack more balls around the perimeter. That does depend on the exact size of the box, though. I just prefer to pack this way, it's more flexible."

They bicker and they quibble, but soon after a while, they both finish packing their identical cube boxes with the maximum possible number of balls, using each of their preferred packing methods. To their surprise, they've packed exactly the same number of balls!

Given that the number of balls is more than 3 dozen, what is the smallest number of balls each could have packed in their identical cube boxes?

It's assumed that both packers start with a layer of a maximum number of balls at the bottom of the box, using their preferred packing methods, and work up a layer at a time.

Reference Note:

If the balls have a radius of \(1\), then

For hexagonal packing

Spacing between levels \(\sqrt { 2 } =1.41421...\)

Spacing between rows \(2\)

For face-centered cubic packing

Spacing between levels \(2\sqrt { \dfrac { 2 }{ 3 } } =1.63299...\)

Spacing between rows \(\sqrt { 3 } =1.73205...\)

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