# Balls, Balls, and Balls!

There are $10$ $\mathrm{\color{#D61F06}{red}}$ balls, $10$ $\mathrm{\color{#3D99F6}{blue}}$ balls, and $10$ $\mathrm{\color{#20A900}{green}}$ balls.

How many different ways can you pick $16$ balls such that there is at least one ball for each color?

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