Permutated Pooled Pascal (Power of 7)

Algebra Level 3

(1+2+3+4+5+6+7)1+7(1+2+3+4+5+6)2+21(1+2+3+4+5)3+35(1+2+3+4)4+35(1+2+3)5+21(1+2)6+7(1)7= ?{ (1+2+3+4+5+6+7) }^{ 1 } \\ + 7 { (1+2+3+4+5+6) }^{ 2 } \\ + 21{ (1+2+3+4+5) }^{ 3 } \\ + 35{ (1+2+3+4) }^{ 4 } \\ +35{ (1+2+3) }^{ 5 } \\ +21{ (1+2) }^{ 6 } \\ +7 { (1) }^{ 7 } \\ = \ ?

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