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Algebra Level 5

(n0)12(n1)+13(n2)+(1)n1n+1(nn)=0.00125{n \choose 0} - \frac 12 {n \choose 1} + \frac 13 {n \choose 2} - \ldots + (-1)^n \frac 1{n+1} {n \choose n} = 0.00125

What is the value of nn that satisfy the equation above?

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